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Just like the code I use /var it works but when i use $me it did not

But in the example it use $me and it works well
Why i can not?

Hi baoecit,
/var/variableName: is used for getting variable value. and
$xyz: is used for getting parameter value.
For ex. for parametes use:
//********************//
//*******************//
//********************//
i.e. $leftkey will be replaced with "Options" and rightkey with "Exit".
----------------------------------------------------------------------
It means that we are declaring a variable xyz with value hi. and whenever we will use {/var/xyz} it will replace with "hi".
Hope this will clear ur queries. :)

Hi baoecit,
/var/variableName: is used for getting variable value. and
$xyz: is used for getting parameter value.
For ex. for parametes use:
//********************//
//*******************//
//********************//
i.e. $leftkey will be replaced with "Options" and rightkey with "Exit".
----------------------------------------------------------------------
It means that we are declaring a variable xyz with value hi. and whenever we will use {/var/xyz} it will replace with "hi".
Hope this will clear ur queries. :)